Using a 5% level of significan

Using a 5% level of significance for a test of the null of H0:= versus the alternative of Ha:≠, the null hypothesis:Use the following data to answer Questions 65 through 68.  Two samples were drawn from two normally distributed populations. For the first ...

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阅读理解-Using a 5% level of significance for a test of the null of H0:= versus the alternative of Ha:≠, the null hypothesis:

Use the following data to answer Questions 65 through 68.  Two samples were drawn from two normally distributed populations. For the first sample, the mean was $50 and the standard deviation was $5. For the second sample, the mean was $55 and the standard deviation was $6. The first sample consists of 25 observations and the second sample consists of 36 observations. (Note:In the questions below, the subscripts "1" and "2" indicate the first and second sample, respectively.)

阅读理解

A.cannot be rejected.

B.should be rejected.

C.cannot be tested using the sample information provided.

我个人认为这个应该是:A

解析:The F-test is appropriate to the equality of population variances. The decision rule is to reject H0 if the computed test statistic, F, exceeds the critical F-value atα/ 2. For the information provided, . At a 0.025 level of significance with d1 = 24 and d2 = 35, F-critical = 2.18. Since F < F-critical (1.44 < 2.18), we fail to reject the null hypothesis.
Professor's Note: Many F-tables do not contain numerator df of 35. If the tables do not contain the exact df you need, interpolate the critical value based on the closet available df values.

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  • Using a 5% level of significan

    Using a 5% level of significance and a hypothesis test structure of H0:≤ 24 versus Ha: > 24, the null hypothesis:Use the following data to answer Questions 65 through 68.  Two samples were drawn from two normally distributed populations. For the first sam

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